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Speaker Inpidence?
- Beowolf
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14 years 11 months ago #7538
by Beowolf
Speaker Inpidence? was created by Beowolf
Hi:
My question is about speaker Inpedence.
I have two 4 ohms speakers.
I would like to know if I am right in my statement that follows.
"If I connect two (2) 4 ohms (impeadence) speakers in series,
would I not endup with a 8 ohms setup?
eg: 4 ohms + 4 ohms = 8 ohms ?
In peralel they would stay as 4 ohms, right?
PS: I wish to place two (2) 4 ohms subwoofers in series in an inclosuer with
two 4 ohms tweeter also in series, and end up with an 8 ohms system.
Please help!
Beowolf
My question is about speaker Inpedence.
I have two 4 ohms speakers.
I would like to know if I am right in my statement that follows.
"If I connect two (2) 4 ohms (impeadence) speakers in series,
would I not endup with a 8 ohms setup?
eg: 4 ohms + 4 ohms = 8 ohms ?
In peralel they would stay as 4 ohms, right?
PS: I wish to place two (2) 4 ohms subwoofers in series in an inclosuer with
two 4 ohms tweeter also in series, and end up with an 8 ohms system.
Please help!
Beowolf
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- cilla.scope
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14 years 10 months ago #7550
by cilla.scope
Replied by cilla.scope on topic Speaker Inpidence?
Nope,
two 4 ohm speakers in parallel will give you 2 ohms
1(1/4 + 1/4) = 2
but .. good news ..
what you need is a crossover .. this will feed the bass to the bass spekers and the treble to the tweeters and still give you 8 ohms on the output
infact you ust use a crossover, even if its as simple as a series C to the tweeters, because feeding bass to the tweters is a sure fire way to kill them
two 4 ohm speakers in parallel will give you 2 ohms
1(1/4 + 1/4) = 2
but .. good news ..
what you need is a crossover .. this will feed the bass to the bass spekers and the treble to the tweeters and still give you 8 ohms on the output
infact you ust use a crossover, even if its as simple as a series C to the tweeters, because feeding bass to the tweters is a sure fire way to kill them
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